Fat is one of six nutrients your body needs to stay healthy. The other five nutrients are:

• Carbohydrates (found in fruits, vegetables, pasta, rice, grains, peas, beans, and other legumes)
• Proteins (found in meat, poultry, dairy products, eggs, and beans)
• Minerals (such as potassium, calcium, and iron)
• Vitamins (such as vitamins A, D, E, and K)
• Water

Of these six nutrients, carbohydrates, protein and fats provide calories. Each gram of carbohydrate and protein yield 4 calories/gram. Each gram of fat yields 9 calories.

A calorie is a measurement, just like a teaspoon or an inch. Calories are the amount of energy released when your body breaks down (digests and absorbs) food. The more calories a food has, the more energy it can provide to your body. When you eat more calories than you need, your body stores the extra calories as body fat. Even a fat-free food can have a lot of calories that eventually will contribute and can be stored as excess body fat.

Why does fat get all of the attention?

Fat gets all of the attention for many good reasons. Consider these facts:

• Some fats can raise cholesterol levels in the blood. A high cholesterol level is a leading risk factor for heart disease.
• Some fatty foods (such as bacon, sausage, and potato chips) often have higher calories with fewer vitamins and minerals than low-fat other foods. (Note: Protein sources, especially red meat and dairy products, often contain fat. Good, low-fat sources of protein include lean meat, fish, poultry without skin, beans, lentils, tofu, low-fat yogurt, low-fat milk, and low-fat cottage cheese, and tuna fish packed in water.)
• Fat has about twice as many calories per gram as carbohydrates and proteins. A gram of fat has about 9 calories, while a gram of carbohydrate or protein has about 4 calories. In other words, you could eat twice as much carbohydrates or proteins as fat for the same amount of calories.

Will I lose weight if I eat low-fat foods?

It’s true that a diet high in fat can lead to weight gain. But it takes more than just eating low-fat foods to lose weight. You must also watch how many calories you eat. Remember, extra calories even from fat-free and low-fat foods get stored in the body as body fat. Many times people replace high-fat foods for high-calorie foods, like sweets, and gain weight rather than lose weight.

To lose weight, you need to burn more calories than you eat. You can achieve this goal by eating less fat and fewer calories, and exercising. Exercise burns calories. (Consult with your health care provider before starting an exercise or diet program.)

How much fat should I eat?

A low-fat style of eating is important for maintaining a healthy weight and preventing heart disease. The American Heart Association recommends limiting total calories from fat to less than 30 percent. That’s about 65 grams of fat or less a day if you eat 2,000 calories a day.

How can I know how much fat I am eating?

• Read nutrition labels on food packages. Nutrition labels show the number of grams of fat per serving. Compare this number to your ‘budgeted’ amount of fat for the day. Food labels They also show the daily percentage of fat provided in each serving. In other words, if the daily percentage of fat per serving is 18%, each serving provides 18% of the total fat you should eat for the day. Choose a brand that has a lower fat percentage. (The daily percentage value is based on a number of calories listed on the nutrition label, usually 2,000. Your calorie needs may be higher or lower.)
• Learn about the foods you eat. Fat and calorie listings for individual foods can be found in nutrition books at your local library and on food packages.

How many grams of fat should I eat each day?

Label claims

Some food labels make claims such as “low cholesterol” or “low-fat.” These claims can only be used if a food meets strict government definitions. Here are some meanings:

TextReader [abstract]
—–> StringReader
—–> StreamReader

TextWriter [abstract]
—–> StringWriter (uses underlying StringBuilder)
—–> StreamWriter

Anomos

“Anomos is a pseudonymous, encrypted multi-peer-to-peer file distribution protocol. It is based on the peer/tracker concept of BitTorrent in combination with an onion routing anonymization layer, with the added benefit of end-to-end encryption. By combining these technologies, we have created a platform where by no party outside of the trusted tracker will have any information about who a peer is or what they are downloading.”

BitBlinder

“Marketers, corporations, criminals, and governments all monitor your online activities. Some even use filters to completely block your access to information. BitBlinder is software that gives you back your online freedom.”

I2P Anonymous Network

“I2P is an anonymizing network, offering a simple layer that identity-sensitive applications can use to securely communicate. All data is wrapped with several layers of encryption, and the network is both distributed and dynamic, with no trusted parties.

Many applications are available that interface with I2P, including mail, peer-peer, IRC chat, and others.”

To that end, I’ve written the following the “remind” myself of these simple tasks…

First, if you’re working with the ObjectDataSource using the DataObjectTypeName property (passing objects in the CRUD methods) the dictionaries passed to the inserting, updating and deleting events are read only by design. If you try to modify these values you will get a “OrderedDictionary is readonly and cannot be
modified.” error. For example, you can’t access an InputParameter and modify it. You can however, access the InputParameter and modify the object it contains! For example in your ObjectDataSource_Updating method…

Location entity = (Location)e.InputParameters["entity"];
entity.CityTownID = some_value;

If you’re not using DataObjectTypeName and are therefore not passing an entity object in your CRUD methods, then you can modify parameters in your ObjectDataSource inserting/updating methods. For example…

e.InputParameters["some_param"] = some_value;

Or if the parameter doesn’t exists…

ObjectDataSource1.UpdateParameters.Add(”some_param”, “some_value”);

ReportItems!tbxMyTextbox.Value

<script>
        function maskedTextbox(evt) {
            var e = evt || window.event;
            var pK = evt.which || e.keyCode;
            var keyPressed = String.fromCharCode(pK);
            var reDigit = /^\d$/;
            var reCTRLChars = /[\x63\x78\x76\x7A]/; // Non-IE: cut, paste, etc. IE lets CTRL operations through.
            var reAllowedCodes = /[\x00\x08\x23\x24\x25\x26\x27\x28\x2D\x2E]/; // arrow keys, ins, del, hom, end, bspace
            if (reCTRLChars.test(keyPressed) || reAllowedCodes.test(keyPressed) || reDigit.test(keyPressed)) {
                return true;
            }
            return false;
        }
</script>

<-- Normal HTML example -->
<input type="text" onkeypress="return maskedTextbox(event);" />

<-- ASP.NET C# example -->
<asp:TextBox ID="txtEmail" onkeypress="return maskedTextbox(event);" runat="server" />

The example demonstrates restricting input to an HTML form element by capturing the onkeypress event. The javascript function will check which key was pressed and return true or false based on whether the keypress is allowed or not. The particular example restricts input to only numbers (ie. 0 to 9). However, there are some other characters we must allow through - INSERT, HOME, DELETE, END, BACKSPACE, and the ARROW keys.

// 'min' and 'max' are inclusive.
function randomNumber(min, max)
{
    return Math.floor((max + 1 - min) * Math.random() + min);
}

// Example: to select a random number between 5 and 20 (inclusive).
var num = randomNumber(5,20);

Uri uri = new Uri("http://www.contoso.com:8080/catalog
/shownew.htm?date=today");
Response.Write("AbsoluteUri: " + uri.AbsoluteUri);
Response.Write("Scheme: " + uri.Scheme);
Response.Write("Host: " + uri.Host);
Response.Write("Port: " + uri.Port);
Response.Write("AbsolutePath: " + uri.AbsolutePath);
Response.Write("PathAndQuery: " + uri.PathAndQuery);
Response.Write("Query: " + uri.Query);
string[] segments = uri.Segments;
foreach (string s in segments)
{
    Response.Write("Segment: " + s);
}
Response.Write("Authority: " + uri.Authority);
Response.Write("HostNameType: " + uri.HostNameType.ToString());
Response.Write("IsDefaultPort: " + uri.IsDefaultPort.ToString());
Response.Write("IsFile: " + uri.IsFile.ToString());

The output:

AbsoluteUri: http://www.contoso.com:8080/catalog/shownew.htm?date=today
Scheme: http
Host: www.contoso.com
Port: 8080
AbsolutePath: /catalog/shownew.htm
PathAndQuery: /catalog/shownew.htm?date=today
Query: ?date=today
Segment: /
Segment: catalog/
Segment: shownew.htm
Authority: www.contoso.com:8080
HostNameType: Dns
IsDefaultPort: False
IsFile: False

Recently discovered the above error (T-SQL, SQL Server) when trying to select DISTINCT rows for one set of columns while ordering the rows by another column.

Jeff Smith had a good explanation of why this occurs (article). In a nutshell, if you’re trying to order your distinct results but the other column you are ordering by is NOT distinct, then how will SQL Server know which value to use for ordering?

The solution is to use a GROUP BY and aggregate function (eg. MAX or MIN) to achieve the same effect. So for example, we do a GROUP BY on our “distinct” columns: column1 and column2. Then we order the results by column3. However, we use an aggregate function (MAX in this example) to ensure SQL Server has a specific column3 value with which to sort by.

SELECT column1, column2
FROM tablename
GROUP BY column1, column2
ORDER BY MAX(column3)

DISTINCT and ORDER BY with 2 non-DISTINCT columns

The above solution didn’t however provide a solution for my specific scenario. I infact had 2 non-distinct columns which I needed to deal with while still selecting distinct rows based on a different set of columns.

I had a [Rank] column by which I wanted to sort the results. The above solution would assist with that. However, I also had a non-distinct [ResultTypeID] column that I also wanted to return in my results. It didn’t matter which ResultTypeID I returned but I still wanted to return a value for this column. The solution? Again, another aggregate function…

SELECT MIN(ResultTypeID), column1, column2
FROM tablename
GROUP BY column1, column2
ORDER BY MAX(Rank)